Evaluate the indefinite integral Solution integral 14 x62 x4

Evaluate the indefinite integral.

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integral (-1+4 x)/(6-2 x+4 x^2)^2 dx For the integrand (4 x-1)/(4 x^2-2 x+6)^2, substitute u = 4 x^2-2 x+6 and du = 8 x-2 dx: = 1/2 integral 1/u^2 du The integral of 1/u^2 is -1/u: = -1/(2 u)+constant Substitute back for u = 4 x^2-2 x+6: = -1/(8 x^2-4 x+12)+constant

Evaluate the indefinite integral. Solution integral (-1+4 x)/(6-2 x+4 x^2)^2 dx For the integrand (4 x-1)/(4 x^2-2 x+6)^2, substitute u = 4 x^2-2 x+6 and du =

Evaluate the indefinite integral Solution integral 14 x62 x4

Solution

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